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摘要:
先进航空发动机燃烧室设计要求对湍流火焰精确控制,现有模拟方法需提高精度和效率。输运概率密度函数(TPDF)湍流燃烧模型精度高,代数二阶矩(ASOM)湍流燃烧模型计算成本低,类比离散涡模拟思想,基于
Da 数将湍流燃烧场区分“高精度”和“低成本”2个区域,在输运方程框架下采用随机场TPDF(高精度)和ASOM(低成本)方法重构TPDF-ASOM复合湍流燃烧模型,以提高模拟的整体精度和效率。在大涡模拟(LES)-TPDF程序平台创建ASOM并进一步实现TPDF-ASOM复合湍流燃烧模型,用Flame D实验数据检验所建模型和方法。结果表明:所建模型的预测结果与实验值接近,而且能够兼顾精度和计算效率。-
关键词:
- 复合湍流燃烧模型 /
- 随机场输运概率密度函数-方程湍流燃烧模型 /
- 代数二阶矩湍流燃烧模型 /
- Da数 /
- Flame D
Abstract:Advanced aero-engine combustor designs require precise control of turbulent flames, and existing simulation methods need to improve accuracy and efficiency. The probability density function transport equation (TPDF) turbulent combustion model possesses high accuracy and the algebraic second-order moment (ASOM) turbulent combustion model low simulation cost. This study uses the
Da number to categorize the turbulent combustion field into “high accuracy” and “low cost” categories, which is similar to the concept of detached eddy simulation (DES). To increase overall accuracy and simulation effectiveness, the TPDF-ASOM composite turbulent combustion model (TAM) was built using the random field TPDF (high accuracy) and ASOM (low simulation cost). This paper created the ASOM model on the large eddy simulation (LES)-TPDF program platform, and further realized the TPDF-ASOM composite turbulent combustion model,which is tested by the Flame D experimental data. The results show that the prediction results of the new model match the experimental values and reconcile the accuracy and simulation efficiency. -
表 1 Flame D火焰边界条件设置
Table 1. Flame D boundary condition settings
边界 边界条件 燃料进口 温度T=293 K,速度U=49.6 m/s 体积分数:甲烷25%,空气75% 值班火焰 温度T=1880 K,速度U=11.4 m/s 已燃气 伴流进口 温度T=293 K,速度U=0.9 m/s 空气 出口边界 压力出口边界 其他边界 绝热固壁无滑移边界 表 2 甲烷JL4机理反应动力学参数
Table 2. Reaction kinetic parameters of CH4 by Xfour-step mechanism
计算式 反应级数 $ A $/(cm3·mol−1·s−1) $ \beta $ $E$/J·mol−1) 式 (16) $\left[\mathrm{CH}_{4}\right]^{0.5}\left[\mathrm{O}_{2}\right]^{1.25}$ $ 7.82 \times 10^{18} $ 0 126 000 式 (17) $ \left[\mathrm{CH}_{4}\right]\left[\mathrm{H}_{2} \mathrm{O}\right] $ $ 0.30 \times 10^{11} $ 0 126 000 式 (18) $\left[\mathrm{H}_{2}\right]^{0.5}\left[\mathrm{O}_{2}\right]^{2.25 }\left[\mathrm{H}_{3} \mathrm{O}\right]^{-1}$ $4.45 \times 10^{18}$ −1 167 000 式 (19) $ [\mathrm{CO}]\left[\mathrm{H}_{2} \mathrm{O}\right] $ $ 2.75 \times 10^{12} $ 0 83 700 -
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