Reliability analysis of nozzle adjustment mechanism with interval distribution parameters
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摘要:
为提高尾喷管调节机构的可靠性分析效率,提出一种结合拒绝采样和主动学习Kriging代理模型的分析方法。在ADAMS中建立了某发动机尾喷管调节机构虚拟样机仿真模型,通过运动学分析对所建模型进行验证;考虑其输入变量含区间分布参数的情形,建立基于调节机构定位精度的极限状态函数;引入主动学习Kriging代理模型,在分布参数随机变化的情况下,通过拒绝采样方法来捕捉样本空间的变化,从而构建适用于整个样本空间内的Kriging代理模型。通过数值算例验证所提方法的可行性,并采用所提方法对调节机构失效概率的上下限进行了计算分析,为提高区间分布参数下的可靠性分析效率提供了一种新的思路。
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关键词:
- 调节机构 /
- Kriging代理模型 /
- 拒绝采样 /
- 区间分布参数 /
- 可靠性
Abstract:To improve the reliability analysis efficiency of the engine nozzle adjustment mechanism, an analysis method combining rejection sampling and active learning Kriging surrogate model is proposed. A virtual prototype simulation model of an engine nozzle adjustment mechanism was established in ADAMS, and the established model is verified by kinematics analysis. Considering the situation that its input variables contain interval distribution parameters, a limit state function based on the positioning accuracy of the adjusting mechanism is established. When distribution parameters change at random, the rejection sampling approach captures the changes in the sample space in order to build a Kriging surrogate model that is appropriate for the full sample space. A numerical example that validates the viability of the suggested approach is used to calculate and analyze the upper and lower boundaries of the adjustment mechanism failure probability. It provides a new method to improve the reliability analysis efficiency under interval distributed parameters.
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表 1 输入变量分布参数
Table 1. Input variable distribution parameters
变量 销轴B半径X1/mm 销轴C半径X2/mm 销轴B处摩擦系数X3 销轴C处摩擦系数X4 阻力矩X5/(N·m) 均值 [2.65, 2.75] [2.65, 2.75] [0.08, 0.12] [0.08, 0.12] [55.92, 60.92] 标准差 0.05 0.05 0.005 0.005 1.120 表 2 悬臂梁问题随机变量分布参数
Table 2. Random variable distribution parameters for cantilever problem
表 3 数值算例可靠性分析结果
Table 3. Reliability analysis results of numerical example
方法 失效概率(下限)/10−4 失效概率(下限)误差/% 失效概率(上限) 失效概率(上限)误差/% 计算时间/s 样本量 候选样本池规模 MCS 4.2 0.2640 AK-MCS 4.7 11.90 0.2646 0.22 733 15+107 31×105 本文方法 4 4.76 0.2643 0.11 124 15+80 92528 表 4 调节机构可靠性分析结果
Table 4. Reliability analysis results of adjustment mechanism
失效概率(下限) 失效概率(上限) 4×10−5 0.0158 -
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